Python Program to count the number of each vowel in a string

Here’s a Python program that counts the number of each vowel in a string:

Approach 1:

# Python program to count the number of each vowel in a string

# input string
string = input("Enter a string: ")

# initialize count variables
a_count = 0
e_count = 0
i_count = 0
o_count = 0
u_count = 0

# iterate through each character in the string
for char in string:
    if char.lower() == 'a':
        a_count += 1
    elif char.lower() == 'e':
        e_count += 1
    elif char.lower() == 'i':
        i_count += 1
    elif char.lower() == 'o':
        o_count += 1
    elif char.lower() == 'u':
        u_count += 1

# print the counts
print("Number of 'a' in the string: ", a_count)
print("Number of 'e' in the string: ", e_count)
print("Number of 'i' in the string: ", i_count)
print("Number of 'o' in the string: ", o_count)
print("Number of 'u' in the string: ", u_count)

 

In this program, we first ask the user to input a string. Then we initialize count variables for each vowel to 0. We then iterate through each character in the string using a for loop, and for each character, we check if it is a vowel (both uppercase and lowercase). If it is a vowel, we increment the corresponding count variable. Finally, we print the counts for each vowel.

 

Approach 2: Program to count the number of each vowel in a string Using function.

# Function to count the number of each vowel in a string
def count_vowels(string):
    # initialize count variables
    a_count = 0
    e_count = 0
    i_count = 0
    o_count = 0
    u_count = 0

    # iterate through each character in the string
    for char in string:
        if char.lower() == 'a':
            a_count += 1
        elif char.lower() == 'e':
            e_count += 1
        elif char.lower() == 'i':
            i_count += 1
        elif char.lower() == 'o':
            o_count += 1
        elif char.lower() == 'u':
            u_count += 1

    # return the counts as a dictionary
    return {'a': a_count, 'e': e_count, 'i': i_count, 'o': o_count, 'u': u_count}

# input string
string = input("Enter a string: ")

# call the function and print the results
vowel_counts = count_vowels(string)
print("Number of 'a' in the string: ", vowel_counts['a'])
print("Number of 'e' in the string: ", vowel_counts['e'])
print("Number of 'i' in the string: ", vowel_counts['i'])
print("Number of 'o' in the string: ", vowel_counts['o'])
print("Number of 'u' in the string: ", vowel_counts['u'])

In this program, we define a function called count_vowels that takes a string as input and returns a dictionary containing the counts of each vowel in the string. The implementation of the function is similar to the previous program, except that instead of printing the counts, we return them as a dictionary.

We then ask the user to input a string and call the count_vowels function with the string as input. We store the returned dictionary in a variable called vowel_counts. Finally, we print the counts for each vowel by accessing the corresponding values in the vowel_counts dictionary.